The corrosion of stainless steel containers in the proposed Yucca Mountain nuclear waste repository in Nevada is a potential problem. One potentially corrosive ion is fluoride, which appears to be removed from solution by precipitation as calcium fluoride. In test measurements, the concentration of calcium ion was found to be 0.00122 M, and the concentration of fluoride ion was found to be 0.0260 g/L. What is the minimum value for Ksp for calcium fluoride based on these measurements ? Use units of moles and liters in your calculation.
What is the minimum Ksp value for calcium floride?
Ksp =[Ca++][F-]^2
0.0260 g F^-1/L = 0.00137 M/L
Ksp = 0.00122 x (0.00137)^2
Ksp = 2.29x10^-9
Reply:1st sonvert g/L into mol/L and then multiply the 2 concentrations at equilibrium together.
Ksp's are always the 2 concentrations at equilibrium multiplied by each other, following all other equilibrium constant eqpression rule.
(exponents etc.)
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